x(x^2+1)(2x+1)=210

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Solution for x(x^2+1)(2x+1)=210 equation: 


Simplifying
x(x2 + 1)(2x + 1) = 210

Reorder the terms:
x(1 + x2)(2x + 1) = 210

Reorder the terms:
x(1 + x2)(1 + 2x) = 210

Multiply (1 + x2) * (1 + 2x)
x(1(1 + 2x) + x2(1 + 2x)) = 210
x((1 * 1 + 2x * 1) + x2(1 + 2x)) = 210
x((1 + 2x) + x2(1 + 2x)) = 210
x(1 + 2x + (1 * x2 + 2x * x2)) = 210
x(1 + 2x + (1x2 + 2x3)) = 210
x(1 + 2x + 1x2 + 2x3) = 210
(1 * x + 2x * x + 1x2 * x + 2x3 * x) = 210
(1x + 2x2 + 1x3 + 2x4) = 210

Solving
1x + 2x2 + 1x3 + 2x4 = 210

Solving for variable 'x'.

Reorder the terms:
-210 + 1x + 2x2 + 1x3 + 2x4 = 210 + -210

Combine like terms: 210 + -210 = 0
-210 + 1x + 2x2 + 1x3 + 2x4 = 0

The solution to this equation could not be determined.

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